• Restaurant Manager
  • Location
    467 Leon Ave, Kelowna, BC, V1Y 6J4, Kelowna, BC| British Columbia
  • Job ID
    40140
  • Views
    5
  • Date Posted
    20-05-2026
  • Expiry Date
    16-11-2026
  • Type of Job
    Full Time
  • Salary
    CAD 40
  • Min. Experience
    1 year to less than 2 years
  • Min. Education
    Secondary (high) school graduation certificate
Job Details
The Kelowna Indian Eatery



Address: 467 Leon Ave, Kelowna, BC, V1Y 6J4

Position: Restaurant Manager

Duration: Full Time Permanent Position

Job Location: 467 Leon Ave, Kelowna, BC, V1Y 6J4

Education: High School

Experience: 1 year to less than 2 years.

Number of openings: 1

Wage: $40.00 /hour for 40 hours per week

Language: English.

Start Date: As soon as possible



Job Duties:

• Overseeing daily operations.

• Hiring, training, and supervising staff.

• Ensuring customer satisfaction by overseeing service quality.

• Handling customer complaints and resolving issues promptly.

• Managing inventory of food, beverages, and supplies.

• Ensuring compliance with health, safety, and sanitation regulations,

• Coordinating with kitchen staff to ensure prompt food preparation and-service.

• Scheduling shifts and ensuring adequate staffing during peak hours.

• Evaluating staff performance and providing feedback.



Work Location Information:

Relocation costs covered by employer

Benefits:

Benefits will be according to BC Employment Standards Act. Relocation Costs Covered by Employer.

Employment Groups:

This employer promotes equal employment opportunities for all job applicants.

How to Apply:

Applicants are encouraged to apply via Email, Mail and in person. We will only contact selected individuals for interviews.

Email-jobsatindianeatery@outlook.com Please mention

"Application for Restaurant Manager" in subject line of mail.

Mail- Mail your resume at 467 Leon Ave, Kelowna, BC, V1Y 6J4

We will contact the selected individual for interview, please do not call or visit in- person.
Job Description