• Restaurant manager
  • Location
    1-700 Tranquille Road, Kamloops, BC| British Columbia
  • Job ID
    38693
  • Views
    8
  • Date Posted
    19-12-2025
  • Expiry Date
    17-06-2026
  • Type of Job
    Full Time
  • Salary
    CAD $36.60 hourly
  • Min. Experience
    2 years to less than 3 years
  • Min. Education
    College/CEGEP
Job Details
Company - Spice of India Cuisine & Sweetshop Ltd.
Position - Restaurant manager
Kamloops, BC
V2B 3H9
Salary
$36.60 hourly / 35 hours per week
Terms of employment
Permanent employment
Full time
Evening, Morning, On call, Day, Weekend
Starts as soon as possible
vacancies -1
Job Description
Overview
Languages
English

Education-
College/CEGEP
Experience-
2 years to less than 3 years

Responsibilities-

Tasks-
Monitor staff performance
Plan and organize daily operations
Recruit staff
Set staff work schedules
Supervise staff
Train staff
Determine type of services to be offered and implement operational procedures
Conduct performance reviews
Ensure health and safety regulations are followed
Negotiate arrangements with suppliers for food and other supplies
Address customers' complaints or concerns
Provide customer service
Plan, organize, direct, control and evaluate daily operations
Prepare budgets and monitor revenues and expenses
Ensure safety procedures are followed

Additional information-

Personal suitability-
Accurate
Efficient interpersonal skills
Flexibility
Organized
Reliability

How to apply-

By email
spicekamloops1@gmail.com

By mail-
1-700 Tranquille Road
Kamloops, BC
V2B 3H9